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1442823742 2015/09/21 17:22:22
\begin{align}
(1 + 2 + \cdots + n)^2 - (1^2 + 2^2 + \cdots + n^2)
&= \left(\sum_{k=1}^n k \right)^2 - \sum_{k=1}^n k^2 \\
&= \{ \frac{1}{2} n(n+1) \}^2 - \frac{1}{6} n(n+1)(2n+1) \\
&= \frac{1}{4} n^2(n^2+2n+1) - \frac{1}{6} n(2n^2+3n+1) \\
&= \frac{n}{12} \left\{ (3n^3+6n^2+3n) - (4^2+6n+2) \right\} \\
&= \frac{n}{12} (3n^3+2n^2-3n-2)
\end{align}
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<IMG SRC="../cgi-cache/20150921_172158.gif">
変換
正常に処理されました
使用できないTeXコマンドがありました
\begin{align}
\end{align}
20150921_172158
http://www.mech.tohoku-gakuin.ac.jp/rde/contents/library/ps2img/eqn2gif_online.html
Mon Sep 21 17:22:22 2015