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1587566021 2020/04/22 23:33:41
\begin{aligned}a_{n}=2\cdot 3^{n-1}-1\\
a_{n}=\dfrac {2}{3}\left\{ 1-\left( -\dfrac {1}{2}\right) ^{n-1}\right\} \\
a_{n}=3\cdot 2^{n-1}-n-1\\
a_{n}=\begin{cases}3^{n}\left( \dfrac {1}{2}n\left( n-1\right) +3\right) \left( n\geqq 2\right) \\
3\left( n=1\right) \end{cases}\end{aligned} \\
\begin{aligned}an=\dfrac {2}{2\cdot 3^{n-1}+1}\\
a_{n+2}-4a_{n+1}+3a_{n}=0\\
a_{n}=\dfrac {1}{2}\left( 3^{n-1}+1\right) \\
b_{n}=\dfrac {1}{2}\left( 3^{n-1}-1\right) \\
a_{n}=\dfrac {1}{3}n\left( n+1\right) \left( n+2\right) \\
\dfrac {1}{2}n\left( n+1\right) \\
n^{3}\end{aligned}\\
\begin{aligned}32-4\\
\dfrac {3}{4}-\dfrac {1}{2\left( n+1\right) \left( n+2\right) }\\
\dfrac {1}{4}n\left( n+1\right) \left( n+2\right) \left( n+3\right) \\
a_{n}=\left( \sqrt {2}\right) ^{n-4}\left\{ 4\sqrt {2}+5+\left( -1\right) ^{n-1}\left( 4\sqrt {2}-5\right) \right\} -3\\
a_{n}=\begin{cases}\left( \sqrt {2}\right) ^{n+3}-3\left( n=2k\right) \\
5\cdot \left( \sqrt {2}\right) ^{n-2}-3\left( n=2k-1\right) \end{cases}\end{aligned}\\
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<IMG SRC="../cgi-cache/20200422_233327.gif">
変換
正常に処理されました
使用できないTeXコマンドがありました
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20200422_233327
http://www.mech.tohoku-gakuin.ac.jp/rde/contents/library/ps2img/eqn2gif_online.html
Wed Apr 22 23:33:41 2020