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\usepackage{algorithm}
\usepackage{algorithmic}
\usepackage{enumerate}
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\begin{algorithm}[t!]
\caption{Solve (8) by ADMM}
\textbf{Input:} tensor data $\X$, parameter $\lambda$.\\
\textbf{Initialize:} $\LL_0=\E_0=\Y_0={0}$, $\rho=1.1$,\\ $\mu_0=1\e{-3}$, $\mu_{\max}=1\e{10}$, $\epsilon=1\e{-8}$. \\
\textbf{while} not converged \textbf{do}
\begin{enumerate}[1.]
\item Update $\LL_{k+1}$ by
\begin{equation*}
\LL_{k+1} = \argmin_{\LL} \ \norm{\LL}_{s}+\frac{\mu_k}{2}\normlarge{\LL+\E_{k}-\X+\frac{\Y_{k}}{\mu_k}}_F^2;
\end{equation*}
\item Update $\E_{k+1}$ by
\begin{equation*}
\E_{k+1} = \argmin_{\E} \ \lambda\norm{\E}_1+\frac{\mu_k}{2}\normlarge{\LL_{k+1}+\E-\X+\frac{\Y_{k}}{\mu_k}}_F^2;
\end{equation*}
\item $\Y_{k+1}=\Y_{k}+\mu_k(\LL_{k+1}+\E_{k+1}-\X)$;
\item Update $\mu_{k+1}$ by $\mu_{k+1}=\min(\rho\mu_k,\mu_{\max})$;
\item Check the convergence conditions
\begin{align*}
& \norm{\LL_{k+1}-\LL_{k}}_\infty\leq\epsilon, \ \norm{\E_{k+1}-\E_{k}}_\infty\leq\epsilon, \\
& \norm{\LL_{k+1}+\E_{k+1}-\X}_\infty\leq\epsilon.
\end{align*}
\end{enumerate}
\textbf{end while}
\label{alg1}
\end{algorithm}
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変換
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\begin{algorithm}
\caption
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\textbf
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\end{algorithm}
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l.39 {\0
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! Emergency stop.
l.39 {\0
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20200823_143552
http://www.mech.tohoku-gakuin.ac.jp/rde/contents/library/ps2img/eqn2gif_online.html
Sun Aug 23 14:38:18 2020