2
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1703213678 2023/12/22 11:54:38
\left(\int_0^\infty \frac{\sin x}{\sqrt{x}}dx\right)^2
=
\sum_{k=0}^\infty\frac{(2k)!}{2^{2k}(k!)^2}\frac{1}{2k+1}
=
\prod_{k=1}^\infty\frac{4k^2}{4k^2-1}
=
\frac\pi2
8
変換(アンチエイリアス)
<IMG SRC="../cgi-cache/20231222_114847.gif">
変換
正常に処理されました
20231222_114847
https://rde.fwex.tohoku-gakuin.ac.jp/rde/contents/library/ps2img/eqn2gif_online.html
Fri Dec 22 11:54:38 2023